Question

cos (π/2)cos(x) + sin(π/2)sin(x) = sin(x)​

Answer 1

Answer:

π/2 radians = 90°

Thus, the given equation's LHS:

= cos 90° × cos (x) + sin 90° × sin (x)

[Since, cos 90° = 0 & sin 90° = 1,]

= 0 × cos (x) + 1× sin (x)

= 0 + sin (x)

= sin (x)

Hence proved, LHS = RHS = sin (x).

Answer 2

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