Question

cos^2 theta-1/4=1/2 ​

Answer 1

{ => Using 'a' in place of theta. }

cos²a-sina = 1/4

(1-sin²a) - sina = 1/4

4-4sin²a-4sina-1 = 0

=> 4sin²a+4sina-3 = 0

=> 4sin²a+6sina-2sina-3 = 0

=> 2sina(2sina+3)-1(2sina+3) = 0

=> (2sina-1)(2sina+3) = 0

since, Sina = -3/2 is not possible

=> Sina = 1/2

=> a = π/6 or 30°

Answer 2

Answer:

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Step-by-step explanation:

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