Question

cos^2 theta * 1 - cos theta / sin^2 theta * 1 - sin theta = 1 + sin theta / 1 + cos theta​

Answer 1

Answer:

LHS=(1−sinθ+cosθ)

2

LHS=1+sin

2

θ+cos

2

θ−2sinθ+2cosθ−2sinθcosθ

LHS=2−2sinθ+2cosθ−2sinθcosθ

LHS=2(1−sinθ)+2cosθ(1−sinθ)

LHS=2(1−sinθ)(1+cosθ)=RHS