Question

cos^2 theta (1 - cos theta) / sin^2 theta (1 - sin theta) = 1 + sin theta / 1 + cos theta​

Answer 1

Step-by-step explanation:

Given

cos^2 theta(1-cos theta)/sin^2theta(1-sin theta)

= [1- sin^2theta= cos^2theta]

(1-sin^2 theta)(1-cos theta)/(1-cos^2theta)(1-sin theta)

common to (1-sin^2theta ) (1-cos theta)

= (1-sin theta)(1-cos theta)[(1+sin theta)]/(1-cos theta)(1-sin theta)[(1+cos theta)]

= (1-sin theta)(1-cos theta) is cancel

= 1+sin theta/1+cos theta