Question

cos^2 theta (1 - cos theta) / sin^2 theta (1 - sin theta) = 1 + sin theta / 1 + cos theta​​

Answer 1

Answer:

sin

2

1

∘

+sin

2

2

∘

+sin

2

2

∘

+...+sin

2

89

∘

+sin

2

90

∘

= (sin

2

1+sin

2

89)+(sin

2

+sin

2

88)+....+(sin

2

44+sin

2

46)+(sin

2

45+sin

9

0)

= (sin

2

1+cos

2

(90−1))+(sin

2

+cos

2

(90−2))+....+(sin

2

44+sin

2

(90−44))+(sin

2

45+sin

9

0)

= (sin

2

1+sin

2

1)+(sin

2

+sin

2

2)+....+(sin

2

44+cos

2

44)+(sin

2

45+sin

9

0)

= 1+1...44times+(

2

1

)

2

+1

= 45+

2

1

= 45.5