Math, asked by koshtishweta79, 4 months ago

=
cos 20º - cos 70°
sin 70°-sin 20°​

Answers

Answered by Nihar1729
0

Answer:

Formula used is (i)  sin (90-θ) = cos θ

                            (ii) cos (90-θ) = sin θ

            \frac{cos \ 20 - cos \ 70}{sin \ 70 - sin \ 20} \\\\= \frac{cos (90 - 70 ) - cos \ 70}{sin\ 70 - sin(90-20)} \\\\=\frac{sin \ 70- cos \ 70}{sin \ 70 - cos \ 70} \\\\= 1 (Ans.)

         Hope it helps

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