Question

Cos 23. Cosec67-sin 23.sec67
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Answer 1

Answer:

0

Step-by-step explanation:

cos 23 = cos (90 - 67)

=sin67. (sin(90 - x) = cosx and cos(90 - x) = sinx)

so, cos23.cosec67 = sin67.cosec.67

= 1. (sinx = 1/cosecx )

and sin23 = sin(90-67)

= cos67

so, sin23.sec67 = cos67.sec67

= 1. (cosx = 1/secx)

so cos 23.cosec67 - sin 23.sec67 = 1 - 1 = 0

Hope this is helpful to you