Question

Cos 27°=x than value of tan 63°

Answer 1

Answer:

4/5

Step-by-step explanation:

A right angled ∆ having angle 27° and 63° has sides of length 3k units , 4k units and 5k units

therefore tan 63° = p/b

= 4/5

Answer 2

Answer:

$\large\boxed{\sf{\dfrac{x}{ \sqrt{1 - {x}^{2} } } }}$

Step-by-step explanation:

Given that,

cos 27 = x

To find the value of tan 63,

We know that,

$\sin( \alpha ) = \sqrt{1 - { \cos }^{2} \alpha }$

Therefore, we will get,

$= > \sin(27) = \sqrt{1 - { \cos }^{2}27 } \\ \\ = > \sin(27) = \sqrt{1 - {x}^{2} }$

Now, we know that,

tan 63

= tan (90- 27)

But, we know that,

• tan (90-@) = cot@

Therefore, we will get,

= cot 27

But, we know that,

• cot@ = cos@/sin@

Therefore, we will get,

= cos27/sin27

= x/√(1-x^2)

Hence, required value is

$\bold{ \dfrac{x}{ \sqrt{1 - {x}^{2} } } }$