Question

cos 28°- sin 58°= sin 2°​

Answer 1

Step-by-step explanation:

cos28°-sin58°

cos28°-sin(90-32)

since, sin(90-A)=cosA

cos28°-cos32°

by using the identity

cosA-cosB= 2sin(A+B)/2,sin(A-B)/2

2sin(60°/2)sin(-4°/2)

2sin30°sin(-2°)

since sin30°=1/2

2×1/2×sin(-2°)

sin(-2°)=sin2°

hence proved.

i hope this will help u