cos^2A + 1/1+cot^2A=1
AbhishGS:
cos.sq.A+1/(1+cot.sq.A) = cos.sq.A+1/cosec.sq.A = cos.sq.A+sin.sq.A =1
please explain this
if u know formulae then u will get how it came
look out every formulas and identities u have
Answers
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Cos.sq.A+1/(1+cot.sq.A)=1
LHS = cos.sq.A+1/(1+cot.sq.A)
=cos.sq.A+1/cosec.sq.A.
....(1+cot.sq.A=cosec.sq.A).
.(.1/sinA=cosecA)
: . cos.sq.A+sin.sq.A...(sin.sq.A+cos.sqA)=1
= 1
LHS = cos.sq.A+1/(1+cot.sq.A)
=cos.sq.A+1/cosec.sq.A.
....(1+cot.sq.A=cosec.sq.A).
.(.1/sinA=cosecA)
: . cos.sq.A+sin.sq.A...(sin.sq.A+cos.sqA)=1
= 1
Attachments:
cos^2A kese 1+cot^2A
nahi
pic bheja hu
dekh lo
Identities txtbook me diya h
vo cosec ^2 A hai
haa
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