cos 2a cos 2 b + sin^2(a- b) - sin^2( a+ b) = cos(2a + 2b)
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Answer:
L
H
S
=
cos
2
A
+
sin
2
A
⋅
cos
2
B
=
1
2
[
2
cos
2
A
+
2
sin
2
A
⋅
cos
2
B
]
=
1
2
[
1
+
cos
2
A
+
(
1
−
cos
2
A
)
⋅
cos
2
B
=
1
2
[
1
+
cos
2
A
+
cos
2
B
−
cos
2
A
⋅
cos
2
B
=
1
2
[
{
1
+
cos
2
B
}
+
{
cos
2
A
(
1
−
cos
2
B
)
}
]
=
1
2
[
2
cos
2
B
+
2
sin
2
B
⋅
cos
2
A
]
=
cos
2
B
+
sin
2
B
⋅
cos
2
A
=
R
H
S
Step-by-step explanation:
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