Math, asked by susantakupanda12, 3 months ago

cos 2A/sec 2A + sin 2A/cosec A=cosA

Answers

Answered by sayandutta38

0

Answer:

the question must be......

cos 2A/sec 2A + sin 2A/cosec 2A=cos A

answer:

cos 2A/sec 2A + sin 2A/cosec 2A=cos A

or, cos^2 2A+sin^2 2A=cos A

or, 1=cos A

or, cos0°=cos A

or, 0°= A

•°• A=0°

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