cos^2A+sin^2A*cos2B=cos^2B+sin^2B*cos2A prove it
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Answer:
LHS=(sinAcosB)
2
−(cosAsinB)
2
=(sinAcosB+cosAsinB)(sinAcosB−cosAsinB)
=sin(A+B)sin(A−B)
=sin
2
A−sin
2
B
=RHS
Step-by-step explanation:
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