Question

Cos^2a+sin^2acos2b=cos^2b+sin^2bcos2a

Answer 1

Answer:

Step-by-step explanation:

L.H.S=cos^2A+sin^2A.cos2B

=cos^2A+sin^2A.(1-2sin^2B) [ since,

cos2A=1-2sin^2A]

=cos^2A+sin^2A-2.sin^2A.sin^2B

=1-2.sin^2A.sin^2B [ since, sin^2A+cos^2A=1]

R. H. S=cos^2B+sin^2B.cos2A

=cos^2B+sin^2B.(1-2sin^2A)

=cos^2B+sin^2B-2.sin^2A.sin^2B

=1-2.sin^2A.sin^2B

L. H. S=R.H.S

hence proved

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