Question

Cos^2A-sin^A=1-2sin^2A

Answer 1

Step-by-step explanation:

$helloo.... \\ { \cos(A) }^{2} - { \sin(A) }^{2} = 1 - 2 { \sin(A) }^{2} \\ L. H. S= > \\ we \: know \: that = > \\ { \cos(A) }^{2} = 1 - { \sin(A) }^{2} ..............(1) \\ \\ Just \: substituting \: the \: values.....\\ \\1 - { \sin(A) }^{2} - { \sin(A) }^{2} \\ 1 - 2{ \sin(A) }^{2} = R. H. S$

Answer 2

$\:\:\:\: \: \: \: \: \: \: \: \: \: \: \large\mathfrak{\underline{\huge\mathcal{\bf{\boxed{\boxed{\huge\mathcal{~~QUESTION~~}}}}}}}$

prove that.....

Cos²A-Sin²A=1-2Sin²A

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$<font color=red><marquee behavior=alternate>Solution</marquee></font>$

L.H.S.=Cos²A-Sin²A

=1-Sin²A-Sin²A

=1-2Sin²A=R.H.S.(proved)

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$<font color=green><marquee direction="Right">hope this help you$

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