Math, asked by rajivkumarsharma9, 9 months ago

cos 2x + 2 sin ^2x = 1

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Answered by Anonymous
16

 \huge \underbrace \mathfrak \blue{Solution}

 \tt \huge \longmapsto \: cos \: 2x + 2 {sin}^{2}  \: x = 1 \\  \\  \tt \huge \longmapsto \: 2 {cos}^{2} x - 1 + 2 {sin}^{2} x = 1 \\  \\  \tt \huge \longmapsto \: 2( {cos}^{2}  \: x +  {sin}^{2}  \: x) - 1 = 1 \\  \\  \tt \huge \longmapsto \: 2 \times 1 - 1 = 1 \\  \\  \tt \huge \longmapsto \: 2 - 1 = 1 \\  \\  \tt \huge \longmapsto \: 1 = 1 \\  \\  \tt \huge \longmapsto \red{hence \: proved}

Answered by ƁƦƛƖƝԼƳƜƛƦƦƖƠƦ
1

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