cos 2x = cos^2x - sin^2x = 2 cos^2x-1=1-2sin^2x= 1-tan^2x/1+tan^2x.......to prove....
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Answered by
3
cos2x=cos(x+x)
=cosx×cosx-sinx×sinx
=cos^2x-sin^2x
cos2x=cos^2x-sin^2x
=cos^2x-1+cos^2x
=2cos^2x-1
cos2x=cos^2x-sin^2x
=1-sin^2x-sin^2x
1-2sin^2x
=cosx×cosx-sinx×sinx
=cos^2x-sin^2x
cos2x=cos^2x-sin^2x
=cos^2x-1+cos^2x
=2cos^2x-1
cos2x=cos^2x-sin^2x
=1-sin^2x-sin^2x
1-2sin^2x
Answered by
3
Answer:
Step-by-step explanation:
cos2x=cos(x+x)
=cosx×cosx-sinx×sinx
=cos^2x-sin^2x
cos2x=cos^2x-sin^2x
=cos^2x-1+cos^2x
=2cos^2x-1
cos2x=cos^2x-sin^2x
=1-sin^2x-sin^2x
1-2sin^2x
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