Cos 2x cos 2y + sin^2 (x-y) - sin ^2 (x+y) = cos (2x+2y)
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Answer:
To prove,
Cos 2x Cos 2y + sin^2(x-y) - sin^2(x+y) {LHS}
cos (2x+2y){RHS}
We can eliminate +sin^2(x-y) and - sin^2(x+y)
Therefore,
LHS= cos 2x cos 2y
= cos (2x+2y)
RHS= cos(2x+2y)
Hence proved, cos(2x+2y)=cos(2x+2y)..
Kudos!
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