Math, asked by veereshk20, 9 months ago

cos^2x-sin^2x=tan^2y then show that tan^2x=cos^2y-sin^2y​

Answers

Answered by VaishnaviMohan
0

Answer:

math]\sin^2 x-\cos^2x=\dfrac {-\sin^2 y}{\cos^2 y}[/math] [math]\dfrac {\sin^2 ... If , then how do you prove that =b

Step-by-step explanation:

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