Question

cos^2x - sinx -1/4=0 solve the degree of x between 0 and 360 or equal.. ​

Answer 1

Answer:

Cos^2x-sinx-1/4=0

1-sin^2x-sinx-1/4=0

-1(-1+sin^2x+sinx+1/4=0

Sin^2x+sinx-3/4=0

4sin^2x+4sinx-3=0

4sin^2x+6sinx-2sinx-3=0

2sinx(2sinx+3)-1(2sinx+3)=0

(2sinx-1)(2sinx+3)=0

Sinx=1/2 or sinx=-3/2

Sinx=-3/2rejected

So, sinx=1/2

Hence, x=30degree