Question

cos^2x - sinx -1/4=0 solve x​

Answer 1

Answer:

4cos^2x-4sinx-1=0

D=b^2-4ac

= 4root sin^2x-cos^2x

quadratic formula

x= 2tan^2,-2tan^2

Answer 2

On L.C.M we get 4 cos ^2 x -- 4 sin x --1 =0

Step-by-step explanation:

4-- 8 sin^2 x -- 4 sin x --1=0

--8 sin^2 x -- 4 sin x +3= 0

8sin ^2 x + 4 sin x--3 =0

on factorization we get sin x = (--1 plus or minus root 7)/4

please make my answer as BRAINLIEST answer