Cos θ = √3/2 then find the value of 1−secθ/1+cosecθ
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- The value of cosθ = √3/2.
- Now using the identity, sin²θ + cos²θ = 1
sin²θ = 1 - (3/4)
sin²θ = 1/4
sinθ = (1/2)
Now, we have to find the value of
1-sec theta/1+cosec theta
Substituting the values in the given expression , we get
Answered by
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value of cosθ = √3/2.
Now using the identity, sin²θ + cos²θ = 1
sin²θ = 1 - (3/4)
sin²θ = 1/4
sinθ = (1/2)
Now, we have to find the value of
1-sec theta/1+cosec theta
Substituting the values in the given expression , we get
\frac{1-sec\theta}{1+cosec\theta}= \frac{1-(1/cos\theta)}{1+(1/sin\theta)}
1+cosecθ
1−secθ
=
1+(1/sinθ)
1−(1/cosθ)
= \frac{1-2/(\sqrt{3})}{1+(2)}=
1+(2)
1−2/(
3
)
= \frac{(\sqrt{3})-2}{3(\sqrt{3})}=
3(
3
)
(
3
)−2
= \frac{3-2\sqrt{3}}{9}=
9 is answer
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