cos(3π÷4+x) - cos(3π÷4-x) =-√2 sinx
Answers
Answered by
13
Answer:
cos(
4
3π
+x)−cos(
4
3π
−x)
=cos
4
3π
cosx−sin
4
3π
sinx−cos
4
3π
cosx−sin
4
3π
sinx
=−2sin
4
3π
sinx
=−2(−sin
4
π
)sinx
=
2
sinx
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