cos(3π÷4+x)-cos(3π÷4-x)=√2sin x
plz prove this.
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Step-by-step explanation:
cos(3Π÷4+x)-cos(3Π÷4-x)
=-2(sin3Π÷4+x+3Π÷4-x/2)sin (3Π÷4+x-3Π÷4-x/2)
=-2sin 3Π÷4 sinx
=-2.1/√2 sinx [sin 3Π÷4=1/√2]
=-√2 sinx
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