Question

cos ( 3 pi by 2plus x) cos( 2pi+x)[cot(3 pi by 2 -x) + cot ( 2 pi+ x)] equal to 1​

Answer 1

Step-by-step explanation:

$cos( \frac{3\pi}{2} + x)cos(2\pi + x)(cot( \frac{3\pi}{2} - x) + cot(2\pi + x) \\ sinxcosx(tanx + cotx) \\ sinx \: cosx( \frac{sinx}{cosx} + \frac{cosx}{sinx} ) \\ sinx \: cosx( \frac{ {sin}^{2}x + {cos}^{2} x }{sinx \: cosx} ) \\ 1 \\ \\ hence \: proved \: \\ hope \: it \: will \: help \: yo.$