Math, asked by aditya25112003, 11 months ago

cos ( 3 pi by 2plus x) cos( 2pi+x)[cot(3 pi by 2 -x) + cot ( 2 pi+ x)] equal to 1​

Answers

Answered by rishabh1894041
5

Step-by-step explanation:

cos( \frac{3\pi}{2}  + x)cos(2\pi + x)(cot( \frac{3\pi}{2}  - x) + cot(2\pi + x) \\ sinxcosx(tanx + cotx) \\ sinx \: cosx( \frac{sinx}{cosx}  +  \frac{cosx}{sinx} ) \\ sinx \: cosx( \frac{ {sin}^{2}x +  {cos}^{2} x }{sinx \: cosx} ) \\ 1 \\  \\ hence \: proved \:  \\ hope \: it \: will \: help \: yo.

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