cos 3 theta = 4 cos³ theta - 3 cos theta
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Answered by
1587
cos3θ=cos(2θ+θ)
=cos2θcosθ−sin2θsinθ
=(cos2θ−sin2θ)cosθ−2sinθcosθsinθ
=cos3θ−sin2cosθ−2sin2θcosθ
=cosθ(cos2θ−sin2θ−2sin2θ)
=cosθ(cos2θ−3sin2θ)
=cos3θ−3sin2θcosθ
=cos3θ−3(1−cos2θ)cosθ
=cos3θ−3cosθ+3cos3θ
=4cos3θ−3cosθ
Thnx
Answered by
3
Answer:
sorry
Step-by-step explanation:
cos3θ=cos(2θ+θ). =cos2θcosθ−sin2θsinθ. =(cos2θ−sin2θ)cosθ−2sinθcosθsinθ. =cos3θ−sin2cosθ−2sin2θcosθ.
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