(cos^3 theta+sin^3 theta)/(costheta+sintheta)+(cos3theta-sin3theta)/(costheta-sintheta)=2
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Answered by
32
Answer:
(Cos³Ø+Sin³Ø)/CosØ+SinØ+(Cos³Ø-Sin³Ø)/CosØ-SinØ
=CosØ+SinØ(Cos²Ø+Sin²Ø)/CosØ+SinØ
CosØ-SinØ(Cos²Ø-Sin²Ø)/ CosØ-SinØ
=Cos²Ø+Sin²Ø + Cos²Ø-Sin²Ø
=1 + Cos²Ø-(1-Cos²Ø)
=1 + 1
=2
Answered by
29
(Answer)=
step by step solution is in the attachment
Explanation=
first used (a^3+b^3) identity to start.
Attachments:
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