cos ^3 theta+ sine^3 theta /cos theta+sin theta +
cos ^3 theta-sin^3 theta/
cos theta - sin theta
=2
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Answer:
(Cos³Ø+Sin³Ø)/CosØ+SinØ+(Cos³Ø-Sin³Ø)/CosØ-SinØ
=CosØ+SinØ(Cos²Ø+Sin²Ø)/CosØ+SinØ
CosØ-SinØ(Cos²Ø-Sin²Ø)/ CosØ-SinØ
=Cos²Ø+Sin²Ø + Cos²Ø-Sin²Ø
=1 + Cos²Ø-(1-Cos²Ø)
=1 + 1
=2
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