(cos(30+Φ)-sin(30+Φ)=?
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Answer:
From the equilateral (60-60-60) triangle with all legs of length 1, we can view half the triangle, forming a 30-60-90 triangle, with the hypotenuse measuring 1, the short leg 1/2, and the long leg 3 2. Therefore, we have sin 30° = 1/2, cos 30° = 3 2, sin 60° = 3 2 and cos 60° = 1/2.
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From the equilateral (30-30-30) triangle with all legs of length 1, we can view half the triangle, forming a 30-30-30 triangle, with the hypotenuse measuring 1, the short leg 1/2, and the long leg 3 2. Therefore, we have sin 30° = 1/2, cos 30° = 3 2, sin 30° = 3 2 and cos 30° = 1/2.
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