Math, asked by subhrobanerjee13, 3 months ago

cos 32° sin 20° + cos 144ºcos 2° + sin 68°cos 56° = 0​

Answers

Answered by vardhanaditya2021
0

Answer:L.H.S = cos32°sin20°+sin68°cos56°+cos144°cos2°

=1/2(2cos32°sin20°+2sin68°cos56°+2cos144°cos2°)

=1/2(sin52°-sin12°+sin124°+sin12°+cos146°+cos142°)

=1/2{sin52°+sin124°+cos(180°-34°)+cos(180°-38°)}

=1/2{sin(90°-38°)+sin(90°+34°)-cos34°-cos38°}

=1/2(cos38°+cos34°-cos34°-cos38°)

=0 R.H.S Proved

Step-by-step explanation:

Answered by yutishkumar
0

Answer:

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