cos 32° sin 20° + cos 144ºcos 2° + sin 68°cos 56° = 0
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Answer:L.H.S = cos32°sin20°+sin68°cos56°+cos144°cos2°
=1/2(2cos32°sin20°+2sin68°cos56°+2cos144°cos2°)
=1/2(sin52°-sin12°+sin124°+sin12°+cos146°+cos142°)
=1/2{sin52°+sin124°+cos(180°-34°)+cos(180°-38°)}
=1/2{sin(90°-38°)+sin(90°+34°)-cos34°-cos38°}
=1/2(cos38°+cos34°-cos34°-cos38°)
=0 R.H.S Proved
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Answer:
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