cos 340 .cos 40 + sin 200.sin140
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Answered by
106
cos 340 * cos 40 + sin 200 * sin 140
cos(360-20)*cos40+sin(180+20)*sin(180-40)
cos20*cos40+(-sin20)*sin40
cos20*cos40-sin20*sin40
cos A * cos B - sin A * sin B = cos(A+B)
so, cos(40+20)= cos60 = 0.5
cos(360-20)*cos40+sin(180+20)*sin(180-40)
cos20*cos40+(-sin20)*sin40
cos20*cos40-sin20*sin40
cos A * cos B - sin A * sin B = cos(A+B)
so, cos(40+20)= cos60 = 0.5
sibhiamar:
no problem
Answered by
36
Answer:
1/2 or 0.5
Step-by-step explanation:
cos 340 . cos 40 + sin 200 . sin 140
[since,
cos 340= cos (360-20) = cos20
sin 200 = sin (180+20) = -sin20
sin 140 = sin (180-40) = sin40]
= cos (360-20) . cos 40 + sin (180+20) . sin (180-40)
= cos 20 . cos 40 + (-sin 20) . sin 40
= cos 20 . cos 40 - sin 20 . sin 40
[ since, cos (A+B) = cos A . cos B - sin A . sin B ]
= cos (20+40)
= cos 60
= 1/2 or 0.5
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