Math, asked by ny7876309, 10 months ago

cos 3A . cos 2A + sin 4A . sin A = cosA.cos2A

Answers

Answered by singhudishapratap

2

Answer:

ANSWER

LHS=(

2sinA

2sinAcosAcos2Acos4Acos8A

)

=(

2×2sinA

2×sin2Acos2Acos4Acos8A

)

=(

2×4sinA

2×sin4Acos4Acos8A

)

=(

2×8sinA

2×sin8Acos8A

)

=(

16sinA

sin16A

)=RHS

Step-by-step explanation:

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