Question

cos^3a+sin^3/COSA+sina =1/2(2-sin^2a). by kartik.k​

Answer 1

Answer:

Formula : -

Formula : -(i) Cos 3 a = 4 cos3 a – 3 cos a

Formula : -(i) Cos 3 a = 4 cos3 a – 3 cos a(ii) sin3a = 3sina – 4sin3a

Formula : -(i) Cos 3 a = 4 cos3 a – 3 cos a(ii) sin3a = 3sina – 4sin3a(iii) a3 – b3 = (a2 – b2)(a2 + b2 + ab)

Formula : -(i) Cos 3 a = 4 cos3 a – 3 cos a(ii) sin3a = 3sina – 4sin3a(iii) a3 – b3 = (a2 – b2)(a2 + b2 + ab)(iv) sin2a + cos2a = 1

Formula : -(i) Cos 3 a = 4 cos3 a – 3 cos a(ii) sin3a = 3sina – 4sin3a(iii) a3 – b3 = (a2 – b2)(a2 + b2 + ab)(iv) sin2a + cos2a = 1Taking L.H.S we get

using formula (i) and (ii)

taking common (cos a – sin a) and using formula (iii)

using formula(iv)

L.H.S = R.H.S

L.H.S = R.H.SHence, Proved.

Answer 2

this is your answer hope it's helpful for you thankyou