Math, asked by 11tripathi, 10 months ago

cos^3a- sin^3a÷ cos a - sin a​

Answers

Answered by kiyakashyap08
1

Answer:

1+cosasina

Step-by-step explanation: As we know that a³-b³=(a-b)(a²+b²+ab)

                                         ⇒ cos³a-sin³a=(cosa-sina)(cos²a+sin²a+cosasina)

                                                                 =(cosa-sina)(1+cosasina)                                 [∵cos²a+sin²a=1]

                                         ⇒(cos³a-sin³a)/(cosa-sina)= 1+cosasina

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