cos^3a- sin^3a÷ cos a - sin a
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Answer:
1+cosasina
Step-by-step explanation: As we know that a³-b³=(a-b)(a²+b²+ab)
⇒ cos³a-sin³a=(cosa-sina)(cos²a+sin²a+cosasina)
=(cosa-sina)(1+cosasina) [∵cos²a+sin²a=1]
⇒(cos³a-sin³a)/(cosa-sina)= 1+cosasina
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