Math, asked by mrLucifer1, 3 months ago

cos( 3pie/2 +x) cos(2pie+x). [ cot ( 3pie/2- x) + Cot (2pie+x]

Answers

Answered by firdousa30

1

Answer:

1

Step-by-step explanation:

cos (3π/2 + x) cos(2π + x).[cot(3π - x) + cot(2π + x)]

=sinx cosx (tanx + cotx)

=sinx cosx (sinx/cosx + cosx/sinx)

=sinx cosx (sin^2 x + cos^2 x / sinx cosx)

= sin^2 x + cos^2x

=1

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