Question

cos 3x = sin2x find general solution ​

Answer 1

Step-by-step explanation:

The general solution of any trigonometric equation is given as –

• sin x = sin y, implies x = nπ + (– 1)ny, where n ∈ Z.

• cos x = cos y, implies x = 2nπ ± y, where n ∈ Z.

• tan x = tan y, implies x = nπ + y, where n ∈ Z.

Given,

⇒

{∵ sin θ = cos (π/2 – θ) }

If cos x = cos y then x = 2nπ ± y, where n ∈ Z

Clearly on comparing we have y = 3x

∴

,

or

∴

or

Hence,

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