cos^4 A -sin^4A=1-sin^2 A
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Answer:
question is wrong in right side
1-2sin2A
Step-by-step explanation:
cos4A=(cos2A) 2
sin4A=(sin2A)2
(cos2A) 2-(sin2A)2 ... a2-b2=(a+b) (a-b)
(cos2A+sin2A)(cos2A-sin2A) ... cos2A+sin2A=1
1(1-sin2A-sin2A) ....cos2A=1-sin2A
1(1-2sin2A)
1-2sin2A
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