Question

cos^4+sin^4-6cos^2sin^2 solve​

Answer 1

Answer:

$cos {}^{4} x + sin {}^{4} x + 2 {sin}^{2} x {cos}^{2} x - 8 {sin}^{2} x {cos}^{2} x =$

$( {sin}^{2} x + {cos}^{2} x) {}^{2} - 8 {sin}^{2} x {cos}^{2}x =$

$1 - 2 \times (2sinx \: cosx) {}^{2} =$

$1 - 2 {sin}^{2} 2x$