Question

cos(40+θ) = sinθ , findθ​

Answer 1

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θ=25°

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If cos(40°+θ) = sinθ , findθ

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To find:- θ in cos(40°+ θ)=sinθ

Given:-cos(40°+ θ)=sinθ

We know that sinθ=cos(90°-θ)

So, put the value

cos(40°-θ)=cos(90°-θ)

$\frac{cos(40°-θ)}{cos}$=(90°-θ)

(40°+θ)=(90°-θ)

θ+θ=90°-40°

2θ=50°

θ=25°

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Hope it helps uh

Answer 2

Answer:

cos (40-Ø) =cos (90-Ø)

cos (40-Ø) /cos=(90-Ø)

(40+Ø)=(90-Ø)

Ø+Ø=90-40

2Ø=50

Ø=50/2

Ø=25

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