Math, asked by palkondaragava, 4 months ago

cos (45° + A) –cos (45°– A)/sin (120° +A) – sin (120°–A) = root
2​

Answers

Answered by supriyagoswami242001
0

cos(45+A)−cos(45−A)

=

2cos(120)sinA

−2sin(45)sinA

=

2

2

=

2

........[sin45=

2

1

,cos(120)=−

2

1

]

Formula Used [cosu−cosv=−2sin(

2

u+v

)sin(

2

u−v

), sinu−sinv=2cos(

2

u+v

)sin(

2

u−v

)]

Similar questions