Math, asked by mukesh182005, 4 months ago

cos 45° ÷ sec30°+cosec30°

Answers

Answered by stunwolf

1

cos45°=1/√2

sec30°=2/√3

cosec30°=2

ATP,

1/√2÷2/√3+2

=√3/(2√2)+2

=(√3+4√2)/2√2

Answered by hassanalihassanali06

4

Answer:

Cos 45°/Sec30°+Cosec30°

1/√2÷1/√3/2+2

1/√2×2/√3+2

2/√2√3+2

2/√6+2 Ans

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