Question

cos^4q-sin^4q= cos^2q - sin^2q​

Answer 1

Answer:

HOPE THIS BRING A SMILE IN YOUR FACE

Step-by-step explanation:

Answer 2

Answer:

(cos^2q) - (sin^2q)

Step-by-step explanation:

(cos^2q)^2 - (sin^2q)^2

                                     because we can write a^4- b^4 = (a^2)^2 - (b^2)^2

=>((cos^2q) - (sin^2q))*((cos^2q) + (sin^2q))

                                    because a^2 - b^2 = (a+b)(a-b)

=> (cos^2q) - (sin^2q)*(1)

                        because (sin^2Q) + (cos^2Q) = 1; square order can be changes

=>(cos^2q) - (sin^2q)