Question

cos 54/ tan 36 = cos 59 cosec 31 ​

Answer 1

I think question should be ----> $\frac{cot54^{\circ}}{tan36^{\circ}}=cos59^{\circ}.cosec31^{\circ}$

we know, cot(90° - A) = tanA

so, cot54° = cot(90° - 36°) = tan36°

cosec(90° - A) = secA

so, cosec31° = cosec(90° - 59°) = sec31°

LHS = cot54°/tan36° = tan36°/tan36° = 1

RHS = cos59°. cosec31°

= cos59° . sec59°

= cos59°. 1/cos59°

= 1

hence, LHS = RHS

Answer 2

hope it will help u bro

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