Cos (540-θ) -sin (630-θ)
a) 0
b) 2 cos θ
c) 2 sinθ
d) sin θ - cos θ
Answers
Answered by
45
cos(540-theta)=-cos (theta)
sin(630-theta) = -cos (theta)
so answer is 0
zero
sin(630-theta) = -cos (theta)
so answer is 0
zero
Answered by
26
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Cos (540 - Ф) - Sin ( 630 - Ф)
Cos (3 x 190 - Ф ) - Sin ( 3 x 180 + 90 - Ф )
-Cos Ф - [-sin(90-Ф)]
-cos Ф - (- cos Ф )
-cos Ф + cos Ф = 0
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Option "a" = 0
Is correct
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Cos (540 - Ф) - Sin ( 630 - Ф)
Cos (3 x 190 - Ф ) - Sin ( 3 x 180 + 90 - Ф )
-Cos Ф - [-sin(90-Ф)]
-cos Ф - (- cos Ф )
-cos Ф + cos Ф = 0
_________________________________________________________
Option "a" = 0
Is correct
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Similar questions
sin(630-θ) = sin(270 - θ) = -cosθ
-cosθ-(-cosθ) = cosθ - Cosθ = 0
Option A must be zero I think because the answer is "0"