cos (540-θ) -sin (630-θ)
a) 10
b) 2 cos θ
c) 2 sinθ
d) sin θ - cos θ
Anonymous:
first option is Zero
mistake in question
0 answer crct h?
plzz check ur question again
yeah answer answer is zero
actually someone gave me this ques to post on brainly nd it has option as 10 only :|
if two geniuses r telling, then it must be 0 only =_=
hmm
arey mena bola tha ^^"
:)) ok dear sister's bye tc
Answers
Answered by
7
cos (540 -θ) = Cos(180 - θ ) = -cos θ
sin(630-θ) = sin(270 - θ) = -cosθ
-cosθ-(-cosθ) = cosθ - Cosθ = 0
Option A must be zero I think because the answer is "0"
sin(630-θ) = sin(270 - θ) = -cosθ
-cosθ-(-cosθ) = cosθ - Cosθ = 0
Option A must be zero I think because the answer is "0"
Answered by
4
Hi friend,
Here is your answer...
By applying trignomentric simple rule!!
First we have to separate the questions according to our convenience.
Cos(540-theta)=cos(3×180-theta)
= (Cos180-theta)= -cos theta
Sin (630-theta)=cos(7×90-theta)
=sin(90-theta). => -cos theta
Now sub.the values in the question.
-Cos theta-(-cos theta)
=-cos theta+cos theta
=0
The value is found to be 0
But there is no answer in the option.
Hope this helps you..
Here is your answer...
By applying trignomentric simple rule!!
First we have to separate the questions according to our convenience.
Cos(540-theta)=cos(3×180-theta)
= (Cos180-theta)= -cos theta
Sin (630-theta)=cos(7×90-theta)
=sin(90-theta). => -cos theta
Now sub.the values in the question.
-Cos theta-(-cos theta)
=-cos theta+cos theta
=0
The value is found to be 0
But there is no answer in the option.
Hope this helps you..
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