Math, asked by davidsahi5656, 1 year ago

Cos 55×cosec35÷tan 5 ×tan25×tan65tan×tan 85
how

Answers

Answered by Kartikpatel5a
0

Answer:

Step-by-step explanation:

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Answered by PalakVerma1
5
Hello dear...
Here is your answer..

 \frac{cos \: 55 \: . \: cosec35}{tan5 \: . \: tan25 \: . \: tan65 \: . \: tan85}

 = \frac{cos55 \: .\: sec(90 - 35) }{tan5 \: . \: tan25 \: . \: cot(90 - 65) \: \: cot(90 - 85)}

 = \frac{cos55 \: . \: sec55}{tan5 \: . \: cot5 \: . \: tan \: 25 \: . \: cot \: 25}

 = \frac{1}{1}

 = 1

Hope helped..
Plz mrk as brainliest...
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