Question

cos 58/sin 32+ sin 22/cos 68- cos 90​

Answer 1

Step-by-step explanation:

We know that,

cos(90−θ)=sinθ

sin(90−θ)=cosθ

tan(90−θ)=cotθ

cscθ=

sinθ

1

sin32

∘

cos58

∘

+

cos68

∘

sin22

∘

−

tan18

∘

tan35

∘

tan60

∘

tan72

∘

tan55

∘

cos38

∘

csc52

∘

=

sin32

∘

cos(90−32)

∘

+

cos68

∘

sin(90−68)

∘

−

sin52

∘

tan(90−72)

∘

tan(90−55)

∘

tan60

∘

tan72

∘

tan55

∘

cos(90−52)

∘

=

sin32

∘

sin32

∘

+

cos68

∘

cos68

∘

−