Question

cos 58/ sin 32 + tan40 / tan (90-50)
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Answer 1

Answer:

1.21613052016

Step-by-step explanation:

cos 58°/sin 32° + sin 22 / cos 68 - cos 38 cosec 52 / √3 (tan 18 tan 35 tan 60 tan 72 tan 55)

sin(90°-32°)/sin 32° + cos(90°-68°)/cos 68° - cos38° sec(90°-38°)/ √3(cot(90-72) cot(90-55) √3 tan72 tan55)

sin32°/sin 32° + cos68 / cos 68 - cos 38 sec 38 / (√3 (cot72 cot55 √3 tan 72 tan 55   )

1+1 -  (cos38/cos38)/√3(1/tan72 1/tan55 √3 tan 72 tan55)

2- 1/3

5/3