Cos 5A + Cos7A/
Sin5A+ sin7A
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Answer:
cos5a+cos7a)/(sin5a+sin7a)=2cos(((5a+7a))⁄2)cos(((5a-7a))⁄2)/2sin(((5a+7a))⁄2)cos(((5a-7a))⁄2)
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