cos^6 + cos^4 + cos^2 = 4
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Answer:
4cos6θcos4θcos2θ
=2cos6θ(2cos4θcos2θ)
=2cos6θ(cos(4θ+2θ)+cos(4θ−2θ))
=2cos6θ(cos(6θ)+cos2θ)
=2cos
2
6θ+2cos6θcos2θ
=1+cos12θ+cos(6θ+2θ)+cos(6θ−2θ)
=cos12θ+cos8θ+cos4θ+1
Step-by-step explanation:
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